?a?????t 3DG9018 ????????3???????e???1 ?t?y?a???1ye?t1??? 1 ?????? 3DG9018 1 npn e??? e?1|a? ?1 ?a? ? ???e ??? ??? vhf ? e3?|?? ?? ??????a ?a?e?o? ?a??e? o?1??? ??e?o? ae?? t o -92 2 ??e? 2.1 ???t? 3y?e1?? t am b = 25 2? y ?? 3? ?o? ???? ??? ???? - l?????1 v ce0 1 5 v ???? - ? ????1 v cb0 3 0 v l??? - ? ????1 v eb0 5 v ????? i c 5 0 m a o?1|a (t a= 25 ) p tot 0 . 4 w ??a t j 1 5 0 ???a? t stg - 5 5 150 2.2 ?2?y 3y?e1?? t am b = 25 1? ? ? 2? y ?? 3? ? o? 2a ? ? ?t ?e? ?e ?? ??? ???? - ??????1? i cb0 v cb =15v , i e =0 0 . 1 a l??? - ??????1? i eb0 v eb =3v , i c =0 0 . 1 a 12l????y????? ??2?? h fe v ce =5v , i c =1m a 2 8 1 9 8 ???? - l???o??1 v cesat i c =10m a, i b =1m a 0 . 5 v ? ?? - l???o??1 v besat i c =10m a, i b =1m a 1 v ???a f t v ce =5v , i c =5m a f=400mhz 7 0 0 mhz 1. 5 1.2 7 5 .3ma x 12 .7mi n 5.3 max 0.4 5 1.2 7 4.2 max 0.4 5 ecb ?? ?-????t?yeo?aa 14 o? ?? 05 10 58 07 22 8-22 68 229 9 ??? 05 10 580 03 60 ? 1 3 12 2 3
?a?????t 3DG9018 3 ?e???? 10 0 0.1 0 0 50 p tot (w) 0.4 0.3 t ( ) 0.5 10 50 5 i c (ma) 10 0 h fe 0.2 p tot -t am b 1????? h fe -i c 1????? t am b =25 v ce =1v 0. 1 0. 01 1 v ce sa t (v ) 1 10 i c (m a ) v be sat (v ) i c (m a ) 5 50 0. 6 1. 2 v besat -i c 1????? v cesat -i c 1????? t am b =25 i c /i b =10 t am b =25 i c /i b =10 ? 2 3 12 2 3
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